Why this piece of code gives error?

1 view (last 30 days)
CostFunction='fun4sn0';
nPop=120;
nVar=4;%nVar=1000;
nPop_Initial=nPop;
nPop_Final=30;
MaxNFE=3e3;
MaxIter0=ceil(MaxNFE/((nPop_Initial+nPop_Final)/2)); % Approximate Maximum Iterations
Cr=0.5;
xmin=[0 0 0 0];
xmax=[10 10 pi pi];
%%%%%%%%%%%
NFE=0;
Gbest.Position=[];
Gbest.Cost=inf;
BestCosts=nan(1,MaxIter0);
nfe=BestCosts;
for i=1:nPop
Velocity(i,:)=zeros(1,nVar); %#ok<*SAGROW>
Position(i,:)=xmin+(xmax-xmin).*rand(1,nVar);
Cost(i)=CostFunction(Position(i,:));
PbestPosition(i,:)=Position(i,:);
PbestCost(i)=Cost(i);
PbestVel(i,:)=Velocity(i,:);
if PbestCost(i)<Gbest.Cost
Gbest.Position=PbestPosition(i,:);
Gbest.Cost=PbestCost(i);
Gbest.Velocity= PbestVel(i,:);
end
end
  2 Comments
Jon
Jon on 20 Apr 2022
what error does it give, please cut and paste entire error message
Sadiq Akbar
Sadiq Akbar on 20 Apr 2022
Thank you very much dear Jon for your response. It gives the following error:
Subscript indices must either be real positive integers or logicals.
Error in WGA1 (line 37)
Cost(i)=CostFunction(Position(i,:));

Sign in to comment.

Accepted Answer

Steven Lord
Steven Lord on 20 Apr 2022
Either make your CostFunction variable a function handle to the fun4sn0 function (which is the approach I'd prefer):
CostFunction= @fun4sn0;
or use feval to evaluate the function by name.
Cost(i) = feval(CostFunction, Position(i, :));
Both of these assume that your function returns a scalar, since you're assigning its output into one element of the Cost variable.
  3 Comments
Image Analyst
Image Analyst on 21 Apr 2022
@Steven Lord messing with function handles and feval() seems like a roundabout way to do it. Is that better than just calling the function directly like I suggested?
Cost(i) = fun4sn0(Position(i,:));
Steven Lord
Steven Lord on 21 Apr 2022
@Image Analyst That is another option, and is the easiest if you want to hard-code the cost function. I think that particular name put me in "this is likely going to be used in some form of optimization" mode and in that case (the "function function" scenario, see ode45, fminsearch, fzero, integral, etc.) to keep the code as a general purpose solver you wouldn't want to hard-code the function.

Sign in to comment.

More Answers (1)

Image Analyst
Image Analyst on 20 Apr 2022
CostFunction is a character array, not an actual function. Did you mean
Cost(i) = fun4sn0(Position(i,:));
instead of
Cost(i)=CostFunction(Position(i,:));
Thorough discussion of the error in the FAQ:

Categories

Find more on MATLAB in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!