# Trouble using split function in matlab

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BA on 22 Jul 2022
Commented: BA on 22 Jul 2022
This question was flagged by Cris LaPierre
Having some trouble w/ my data.
The dates are showing up wrong. For example:
3/9/9102
3/10/9102
Obviously, i didn't collect data in 9102 and if you read it backwards, its 2019 which would be the correct date.
Does anyone know how to correct for this?
For example, how would you convert
3/9/9102 --> 3/9/2019
If someone knows, let me know. Thanks
Someone helped me and gave me this code but unfortunately, it doesn't work for multiple dates in a column. It does work for one date though to reverse the year to 2019, it just doesn't work for multiple dates
%For just a single date, it works.
date = ['3/11/9102']
date = '3/11/9102'
newdate = split(date, '/');
newdate(3) = reverse(newdate(3));
newdate = char(join(newdate, '/'))
newdate = '3/11/2019'
%For multiple dates in a column, it doesn't work.
dates = ['3/11/9102'; '3/12/9102'; '3/13/9102'; '3/14/9102'; '3/15/9102';];
splitter = split(dates,'/');
Error using split
First argument must be text.
splitter(3) = reverse(splitter(3));
dates_new = char(join(splitter,'/'));
If you have a solution, please let me know! Thanks

Akira Agata on 22 Jul 2022
% Example
dates = {'3/11/9102'; '3/12/9102'; '3/13/9102'; '3/14/9102'; '3/15/9102'};
% Split by '/', apply fliplr function to '9102' and concatenate
c = split(dates, '/');
c(:, 3) = cellfun(@fliplr, c(:,3), 'UniformOutput', false);
datesNew = join(c, '/');
% Show the result
disp(datesNew)
{'3/11/2019'} {'3/12/2019'} {'3/13/2019'} {'3/14/2019'} {'3/15/2019'}
##### 2 CommentsShowHide 1 older comment
BA on 22 Jul 2022
Both work great, thanks a lot guys!

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