Obtain variable name in TLC

3 views (last 30 days)
I am creating a TLC file for my S-Function and I would like to produce c-code to determine the size of my vector-output-signal array via the sizeof function.
However, both LibBlockInputSignalAddr(0, "", "", 0) and LibBlockInputSignal(0, "", "", 0) only return a reference to the first element of the output signal, thus, sizeof will only return the size of one element of the corrsponding array:
sizeof testModel_Y.Outport[0]
Instead I would like to achieve:
sizeof testModel_Y.Outport
Is it possible generate this statement using a TLC file?

Accepted Answer

Andy Bartlett
Andy Bartlett on 22 Jul 2022
Consider doing it in two parts
bytes = LibBlockInputSignalWidth(0) * sizeof( LibBlockInputSignal(0, "", "", 0) )
  1 Comment
Alexander Sinn
Alexander Sinn on 25 Jul 2022
Thank you for the answer.This is the workaround I am currently using.
I was hoping to eliminate the multiplication but this seems not to be possible.

Sign in to comment.

More Answers (1)

Walter Roberson
Walter Roberson on 25 Jul 2022
In C,
sizeof testModel_Y.Outport
is the size of the pointer contained in testModel_Y.Outport . Multiplying the size of one element by the number of elements is the standard way to measure size of an array in C.
  1 Comment
Alexander Sinn
Alexander Sinn on 25 Jul 2022
According to https://docs.microsoft.com/en-us/cpp/c-language/sizeof-operator-c?view=msvc-170 above code would return the size of the array instead of the pointer: When you apply the sizeof operator to an array identifier, the result is the size of the entire array rather than the size of the pointer represented by the array identifier.
This is also in accord with my testing of this operator.

Sign in to comment.

Products


Release

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!