How do I plot A=sin(pi*y/2)i - sin(pi*x/2)j using QUIVER
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How do I plot A=sin(pi*y/2)i - sin(pi*x/2)j (where i unit vector in x, j unit vector in y, A resultant vector. x range +/-0.5 ; y range +/-0.5 ). using QUIVER.
Accepted Answer
the cyclist
on 7 Oct 2011
x = -0.5:0.05:0.5;
y = -0.5:0.05:0.5;
[xx,yy] = meshgrid(x,y);
Ai = sin(pi*yy/2);
Aj = - sin(pi*xx/2);
quiver(xx,yy,Ai,Aj)
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on 7 Oct 2011
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