how to choose matrix columns randomly?
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hi all. i have two related matrices (A and B). i want to choose randomly 80% of one matrix's columns (e.g A) and corresponding values from second matrix(B)for example:
suppose that two matrices are like this:
A=[1 2 3 4 5 6 7 8 9 10];
B=[11 12 13 14 15 16 17 18 19 20];
desired matrices are for example like:
C=[1 3 4 5 7 8 9 10]
D=[11 13 14 15 17 18 19 20]
would you help me on this? thank you
4 Comments
Stephen23
on 23 Feb 2015
How many columns does A have? What is 80% of one column? What is 80% of two columns? How do you define "80% of one matrix's columns" ?
maryam
on 23 Feb 2015
the cyclist
on 23 Feb 2015
Edited: the cyclist
on 23 Feb 2015
Do you want the 160 to be unique, or possibly repeating? For example, might you choose the 5th column twice?
Also, do you have the Statistics Toolbox? A couple commands there make this a bit cleaner.
maryam
on 23 Feb 2015
Accepted Answer
More Answers (2)
the cyclist
on 23 Feb 2015
1 vote
As Stephen's questions suggest, you need some more specification.
Possible elements of the solution are
- randi, randsample, or other commands to select some random indices. (Say that vector of random indices is called idx )
- Something like either B(:,idx) or B(:,A(idx)) to choose from B directly with the indices, or using values from A that are selected by the indices
1 Comment
the cyclist
on 23 Feb 2015
idx = randsample(200,160);
C = A(idx);
D = B(idx)'
Jos (10584)
on 23 Feb 2015
Exactly 80 vs 20? Or in approximation? And how many columns? I also assume the number of rows in A and B are the same.
A suggestion is that you first draw N columns from A and M columns from B, where N/M is 80/20
Ntotal = 10 ;
N = ceil(.8 * Ntotal) % fixed 80 vs 20
% or
% N = sum(rand(100,1)<0.8)) % roughly
M = Ntotal - N
% select N columns from A and M columns from B
cidxA = randi([1 size(A,2)],1,N)
cidxB = randi([1 size(B,2)],1,M)
% stick them together
OUT = [A(:,cidxA) B(:,cidxB)]
% randomise the order
r = randperm(size(OUT,2))
OUT = OUT(:,r)
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