regarding cropping a polygon out of an image
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hi folks can anybody help me with cropping a polygon out of the image?
i used the following code
I=dicomread('100.ima');
figure,imshow(I,[]);
h=impoly;
position=wait(h);
its providing the option for configuring the required polygon.i have also said it to copy figure.
how can i see only the cropped image?
can anyone help with imcrop()to see the output
Accepted Answer
More Answers (2)
Jan
on 22 Feb 2011
Do you want to crop a rectangle from the image? Or mask a polygone?
figure
img = imread('pout.tif');
imshow(img);
h = impoly;
position = wait(h);
x1 = min(position(:, 1));
x2 = max(position(:, 1));
y1 = min(position(:, 2));
y2 = max(position(:, 2));
BW = createMask(h);
img(~BW) = 255;
img = img(x1:x2, y1:y2);
% Or if img is a 3D RGB array:
% img(~cat(3, BW, BW, BW)) = NaN;
% img = img(x1:x2, y1:y2, :);
figure;
image(img);
8 Comments
ramakrishna bathini
on 23 Feb 2011
Jan
on 23 Feb 2011
Did you try the to apply the mask by "img(~BW) = 255;
" or "img(~cat(3, BW, BW, BW)) = NaN;"? This should disable all not-masked pixels.
ramakrishna bathini
on 24 Feb 2011
Jan
on 24 Feb 2011
What is "it" and what is "the thin strip of line"? When I use the above code, I can cut out the rectangle around an arbitrary polygone and all pixels outside the polygone are white. Please post, what you have done exactly - using one of the example pictures shipped with Matlab.
Jan
on 24 Feb 2011
What is "it" and what is "the thin strip of line"? Please let me not guess the details, but post, what you have done exactly - using one of the example pictures shipped with Matlab. When I use the above code, I can cut out the rectangle around an arbitrary polygone and all pixels outside the polygone are white.
ramakrishna bathini
on 24 Feb 2011
manoj sambasivam
on 16 May 2012
Hi Jan simon,i have small doubt sir, regarding the program.after i select the polygon , what should i do to crop the polygon out of image and save it separetely?
Image Analyst
on 16 May 2012
You do know that images have to be rectangular, don't you? You do know that you can't have a polygonal image, right? (Looks like your answer would be "no") Even if the information is in a polygon shape, you still have to have something (like zeros) to make it a rectangular image.
Alex Taylor
on 16 May 2012
Also, if you DO intend to apply a polygon mask to an image, there are easier ways of doing it. The function roipoly is designed for interactively creating a mask of an arbitrary polygon:
doc roipoly
For example:
I = imread('pout.tif');
imshow(I);
BW = roipoly
Imasked = zeros(size(I),class(I));
Imasked(BW) = I(BW);
imshow(Imasked)
5 Comments
Maria
on 25 Aug 2012
I have got two questions regarding your code Alex
1. How can we do the same thing but for colored images because I have tried running your code for colored ones and it outputs red colored polygon of an image(probably which is the red channel of an image).
2.What if I want to do further processing only on image pixels within the polygon of the same image including the boundary.How should I select those pixel values only?
Image Analyst
on 25 Aug 2012
It will work with this adaptation:
BW = roipoly
% Mask the image.
maskedRgbImage = bsxfun(@times, rgbImage, cast(BW,class(rgbImage)));
% Display it.
imshow(maskedRgbImage);
Maria
on 26 Aug 2012
Thank you Image Analyst and What about my second question
vidya
on 10 Sep 2012
Maria,
I am looking for an answer to your second question, were you able to find a solution, if yes can you share, if not can someone help me too. I also am trying to find a method that can help process only selected image pixels within a polygon for colored images, -Many thanks for your help
Image Analyst
on 10 Sep 2012
It depends on what kind of process you want to do: area processes and point processes would be done in different ways. Area processes (like blurring) need masking while point processes don't necessarily need extra masking steps (for example taking the average = mean(grayImage(maskImage))). Why don't you start a new thread and upload your image and tell us what you want to measure?
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