Nested loop for matrix

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Mitali Murkar
Mitali Murkar on 15 Dec 2022
Commented: Voss on 17 Dec 2022
Below is my code. I want to calculate the value of g where my for loop iterates for i and K. It means I hould have 6 combinations of output.However, I am only getting 3 combinations of output saved in g. Could you please provid the hint or feeback on it? Thanks!
clc
clear all;
ED = readmatrix("Data filteration1.xlsx");
ki = 0.0042; %%current temp coeff
Ns=72; %%72cells in series and 1 in parellel
Np=1;
Ego=1.1;
K= 1.380*10^-23;
q= 1.602*10^-19;
Voc=48.37;
Isc=10.27;
G=[1000 800];
Tck = [25+273 20+273];
I=zeros(400,1);
Vi=ones(400,1);
X= [1.53 0.35 700;1 0.3 600;1.1 0.33 750];
x3=X(:,1);
x4=X(:,2);
x5=X(:,3);
for i=1:length(Tck) % I=2
for k=1:size(X,1) %k=3
Vt(k,i) = K.*Tck(i)/q;
Iph(k,i)= (Isc + ki .* (Tck(i)-298)).*(G(i)./1000);
Irs(k,i) = Isc./((exp((q.*Voc)./(x3(k,:).*Ns.*K.*Tck(i))))-1);
Io(k,i) = Irs(k,i).* (Tck(i)./298).^3 .* exp(((q.*Ego)./(x3(k,:).*K))*(1./298 - 1./Tck(i)));
g(k,:) = (Np.*Iph(k,i))-Io(k,i).*(exp((Vi+I.*x4(k,:))./Vt(k,i)/Ns./x3(k,:))-1)-((Vi+ I.*x4(k,:))./x5(k,:)) - I;
end
end

Accepted Answer

Voss
Voss on 15 Dec 2022
clc
clear all;
% ED = readmatrix("Data filteration1.xlsx");
ki = 0.0042; %%current temp coeff
Ns=72; %%72cells in series and 1 in parellel
Np=1;
Ego=1.1;
K= 1.380*10^-23;
q= 1.602*10^-19;
Voc=48.37;
Isc=10.27;
G=[1000 800];
Tck = [25+273 20+273];
I=zeros(400,1);
Vi=ones(400,1);
X= [1.53 0.35 700;1 0.3 600;1.1 0.33 750];
x3=X(:,1);
x4=X(:,2);
x5=X(:,3);
nT = length(Tck);
nX = size(X,1);
g = zeros(nT*nX,numel(I));
row = 1;
for i=1:nT % I=2
for k=1:nX %k=3
Vt(k,i) = K.*Tck(i)/q;
Iph(k,i)= (Isc + ki .* (Tck(i)-298)).*(G(i)./1000);
Irs(k,i) = Isc./((exp((q.*Voc)./(x3(k,:).*Ns.*K.*Tck(i))))-1);
Io(k,i) = Irs(k,i).* (Tck(i)./298).^3 .* exp(((q.*Ego)./(x3(k,:).*K))*(1./298 - 1./Tck(i)));
g(row,:) = (Np.*Iph(k,i))-Io(k,i).*(exp((Vi+I.*x4(k,:))./Vt(k,i)/Ns./x3(k,:))-1)-((Vi+ I.*x4(k,:))./x5(k,:)) - I;
row = row+1;
end
end
size(g)
ans = 1×2
6 400
  2 Comments
Mitali Murkar
Mitali Murkar on 17 Dec 2022
Hello Voss, thank you so much for the hint. It works now! Very helpful.
Voss
Voss on 17 Dec 2022
You're welcome!

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More Answers (1)

the cyclist
the cyclist on 15 Dec 2022
I'm guessing you intended
g(k,i)
rather than
g(k,:)
in the last line of the for loop.
  3 Comments
the cyclist
the cyclist on 15 Dec 2022
I'm not certain why you think it should be 6*400. If you look at your indexing, here is what happens during all the iterations of your for loops:
i==1, k==1
Write g(1,:)
i==1, k==2
Write g(2,:)
i==1, k==3
Write g(3,:)
i==2, k==1
Over-write to g(1,:)
i==2, k==2
Over-write to g(2,:)
i==2, k==3
Over-write to g(3,:)
===========================
Notice that you never use i to index into g, so you are overwriting instead of creating rows 4-6.
Mitali Murkar
Mitali Murkar on 17 Dec 2022
Thank you so much for clarification and your very prompt response.

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