How can I put variable equal to zero in loop

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in this code
w= input('k=');
for k=1:w
m=sym('U1',[1 k])
end
I need to put U1k in every iteration =0
U11=0
U12=0
U13=0 .......
  1 Comment
Adham Ahmed
Adham Ahmed on 8 Feb 2023
thank you
I need for k=1
U11=0
for k=2
U12=0
for k=3
U13=0
an so on.........
for k=9
U19=0
using loop

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Answers (3)

Dinesh
Dinesh on 8 Feb 2023
Hi Adham Ahmed,
For any input 'w', to create that many number of variables during run time, 'sprintf' function can be used.
Then the 'eval' function can be used to initialize them to zero as you wanted to do.
The following code takes an input 'w' and then creates that many number of variables namely U11, U12, ...., U1w at run time and initializes all of them to zero.
w = input('k='); % takes an input 'w'
for k = 1:w
var_name = sprintf('U%d%d', 1, k); % creates the dynamic variable name
eval([var_name '= 0;']); % initialization to zero
end
In the above code, for an example, if the input 'w' is 3, then you can print 'U13' using
disp(U13);
to confirm the variable creation and value assignment.
  2 Comments
Steven Lord
Steven Lord on 8 Feb 2023
Can you dynamically create variables with numbered names like U11, U12, U13, etc.? Yes.
Should you do this? The general consensus is no. That Answers post explains why this is generally discouraged and offers several alternative approaches.
Adham Ahmed
Adham Ahmed on 8 Feb 2023
thank you
I need for k=1
U11=0
for k=2
U12=0
for k=3
U13=0
an so on.........
for k=9
U19=0
using loop

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VBBV
VBBV on 8 Feb 2023
% using loop
w= 10; %input('k=');
for k=1:w
m=sym('U1',[1 k]) == 0;
end
m
m = 
you can also do so without using loop
% without loop
m=sym('U1',[1 w]) == 0
m = 
  2 Comments
Adham Ahmed
Adham Ahmed on 8 Feb 2023
thank you
but only the last one to be zero
Adham Ahmed
Adham Ahmed on 8 Feb 2023
thank you
I need for k=1
U11=0
for k=2
U12=0
for k=3
U13=0
an so on.........
for k=9
U19=0
using loop

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Shubham
Shubham on 8 Feb 2023
Here's a code that sets the symbol 'U1k' to zero in each iteration:
w = input('k=');
for k = 1:w
eval(sprintf('U1%d=0', k))
end
  1 Comment
Adham Ahmed
Adham Ahmed on 8 Feb 2023
thank you
I need for k=1
U11=0
for k=2
U12=0
for k=3
U13=0
an so on.........
for k=9
U19=0
using loop

Sign in to comment.

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