Reading a single numerical value from regexp return
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I'm searching though text logs and recoridng the number of errors that occur. I want to take the error number after finding it and save it to a variable from the cell array but can't seem to get numerical value out of the cell aray.
The error log looks like the following
Success
Error 303
Success
Completed
Error 301
File
Here is what my code look like at the moment. I get an error when tring to compare the error code to cell array contents.
A = importdata('history_log_28.txt');
numLines = length(A);
Error_301_Count = 0;
Error_302_Count = 0;
Error_303_Count = 0;
for i= 1:numLines
GrabLine = A(i,:);
Error_Catch = regexp(GrabLine,'Error (\w*)','tokens');
if (Error_Catch{1} == '303')
Error_303_Count = Error_303_Count + 1;
end
end
1 Comment
Stephen23
on 24 Mar 2023
Edited: Stephen23
on 24 Mar 2023
"I want to take the error number after finding it and save it to a variable from the cell array but can't seem to get numerical value out of the cell aray. "
There is no numeric value in that cell array, for the very simple reason that REGEXP does not return numeric values from the input text, it returns text. If you want to convert text to numeric, then you can use the usual approaches, e.g. STR2DOUBLE or SSCANF or the like.
Accepted Answer
Stephen23
on 24 Mar 2023
Edited: Stephen23
on 24 Mar 2023
Get rid of the loop and process the entire file at once. Line-by-line just makes it more complex.
You can get rid of one layer of cell arrays by using a look-behind instead of the token. That simplifies the post-processing.
Don't reinvent the wheel (binning) when it already exists in one efficient function.
txt = fileread('test.txt')
tmp = regexp(txt,'(?<=Error\s*)\d+','match');
vec = str2double(tmp) % errors found in the file
cnt = histcounts(vec,[301:303,Inf]) % count 301, 302, 303.
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