how can Matlab's filter() function generate the output y[n] when the input is given by the plot in the image with input long enough to see all the non-zero values of y[n].

[Walter Roberson]

You can read off the signal input values... but in order to work with filter() you need to know the filter coefficients.

[Chuki Ocheje]

That is exactly what I do not know

Answer 1

[Walter Roberson]

Since no constraints are given on what the output signal should look like, you might as well make the output be exactly the same as the input.

x = [1 4 3 2 3]

x = 1×5

1 4 3 2 3

subplot(2,1,1); stem(x); title('input signal')
y = filter(1,1,x)

y = 1×5

1 4 3 2 3

subplot(2,1,2); stem(y); title('output signal')

[Chuki Ocheje]

Is that all you need to do?

[Walter Roberson]

That is all you have asked for. I would imagine that in context the y[n] that needed to be matched was defined in a previous part of the question.

[Chuki Ocheje]

This was the whole question before that one

[Walter Roberson]

Well, what was the result of your (e) ? The "overall cascade system" is the y[n] that they are looking for.

[Chuki Ocheje]

for the overall cascade system, it was y[n] = 2x[n-4] + 3x[n-3] - 2x[n-5] + 4x[n-2] - x [n-1] (p.s. this is the difference equation of it )

[Paul]

What does that notation for h2[n] mean? I'm not familiar with that brace-and-arrow ...