why is this not outputting the correct values

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triangle:1
Side A: 3
Side B: 3
Hypotenuse: 6
Side A: 3
Side B: 6
Hypotenuse: 4
triangle:2
Side A:
Side B: 6
Hypotenuse: 6
Side A: 4
Side B: >>
this is the output when I run this script where as I expected to get only two outputs of a's and such, also where could the code have gotten so many values of 3.
pythtrips=[3 4 5;6 8 10]
for i=1:size(pythtrips,1)
e=pythtrips(i:1);
f=pythtrips(i:2);
g=pythtrips(i:3);
fprintf('triangle:%d\n',i)
fprintf('Side A: %d \nSide B: %d \nHypotenuse: %d \n' ,e,f,g)
end

Accepted Answer

Star Strider
Star Strider on 25 Nov 2023
There is a syntax error, in that you used a colon operator ‘:’ instead of a comma in the ‘pythtrips’ references. The syntax is ‘legal’ in the sense that the colon operator creates a vector (so it would not have thrown an error), however its behaviour was not what you intended.
Try this —
pythtrips=[3 4 5;6 8 10]
pythtrips = 2×3
3 4 5 6 8 10
for i=1:size(pythtrips,1)
e=pythtrips(i,1);
f=pythtrips(i,2);
g=pythtrips(i,3);
fprintf('triangle:%d\n',i)
fprintf('Side A: %d \nSide B: %d \nHypotenuse: %d \n' ,e,f,g)
end
triangle:1
Side A: 3 Side B: 4 Hypotenuse: 5
triangle:2
Side A: 6 Side B: 8 Hypotenuse: 10
.

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