How to calculate center of pressure given a 2d array containing pressure data
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So as the title says I want to know how to calculate the center of pressure coordinates given that the input will be a 2d matrix with each element representing a "pressure grid".
3 Comments
the cyclist
on 13 Mar 2024
Edited: the cyclist
on 13 Mar 2024
Do elements with index 1,2,3 ... representing points that are equally spaced in the "real world"? Is the spacing the same along the two dimensions?
Accepted Answer
the cyclist
on 13 Mar 2024
Edited: the cyclist
on 13 Mar 2024
If the answers to both of the questions in my comment is "yes", then
% Example input
pressureArray = [1 2 3;
4 5 6;
7 8 9]
% Get array size
[rows, cols] = size(pressureArray);
% Total pressure
totalPressure = sum(pressureArray,"all");
% Calculate moments about x and y axes
momentX = sum((1:cols) .* pressureArray,"all");
momentY = sum((1:rows)' .* pressureArray,"all");
% Calculate center of pressure
COP_x = momentX / totalPressure
COP_y = momentY / totalPressure
The "spatial" coordinates are the indexing of the array (in this case 1:3 along both directions). You may need to apply a multiplier, or translation operation.
More Answers (1)
Image Analyst
on 14 Mar 2024
If you have the Image Processing Toolbox (I think most people do) then you can do it in one line of code by asking regionprops to compute the weighted centroid.
% Example input from the cyclist
pressureArray = [1 2 3;
4 5 6;
7 8 9];
% Using regionprops to compute the weighted centroid. Requires Image Processing Toolbox.
props = regionprops(true(size(pressureArray)), pressureArray, 'WeightedCentroid')
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