What am I supposed to put in magnetization inductance?
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Hi,
I want to simulate this push-pull DC-DC converter in simulink:

I am modifying the magnetization inductance (Lm) for a value that is appropriate for my specs: Vin = 137.14 V (it comes from a previous stage),Vout = 350 V, D = 0.13, Iin = 7 A (approx.). I see that even if I set it in SI units, it says (pu) for the magnetization inductance. It confuses me because I was trying to have 1 mH or 10 mH to avoid an overvoltage and I don't know in which units it's actually. I was also trying with higher values of Lm but I have that peak at the beginning. In fact I have seen 2 situations.
A) Overvoltage, then stabilizes but the value was a few volts far from the reference. This is the case when magnetization inductance is 0.0.
B) Overvoltage, then starts dropping to 155 V.
Can someone tell me what are the expected values in the parameters of the transformer for such specs and in which units is calculating Lm when I set it in SI units?

Also, the input current has this aspect:

Thanks.
Carlos
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Answers (1)
sneha
on 12 Nov 2025 at 9:03
Hello,
In your push-pull DC-DC converter model, the magnetizing inductance (Lm) value is shown in per-unit (pu) because Simulink normalizes it using the transformer’s base voltage, base current, and frequency.
That means even if you enter Lm in Henrys (H), Simulink converts and displays it as a relative (pu) value, it doesn’t change the actual inductance used in simulation.
Helpful MathWorks Documentation:
Per-Unit System (Simscape Electrical)
explains how Simulink converts SI values to per-unit.
Transformer Block Reference
shows parameter units, base values, and how magnetizing inductance (Lm) is defined.
Push-Pull Converter Example
demonstrates proper transformer parameterization and flux balancing.
DC-DC Converter Examples
“Avoiding DC bias in push-pull” section explains flux reset and why startup spikes occur.
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