How to find the day number of any year from a date?
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Md. Golam Mostafa
on 23 Jul 2015
Edited: Sergey Kostrukov
on 12 Feb 2022
I am very new in programming and therefore it is probably a novice's question. I have to write a script that takes a number of day(dd), month(mm) and year(yyyy)values arranged in three separate columns of a MATLAB variable and gives the day number of the year(e.g. for 03 March 2012, 31+29+3=63) as output.
2 Comments
Accepted Answer
Peter Perkins
on 23 Jul 2015
If you are using R2014b or later, the datetime data type allows you to compute the day of year using the day function:
>> x = [2012 1 2; 2012 3 3; 2013 3 3]
x =
2012 1 2
2012 3 3
2013 3 3
>> d = datetime(x)
d =
02-Jan-2012
03-Mar-2012
03-Mar-2013
>> day(d,'dayofyear')
ans =
2
63
62
2 Comments
Peter Perkins
on 24 Jul 2015
Presumably, you are not "using R2014b or later". datetime did not exist prior to that.
More Answers (3)
Andrei Bobrov
on 24 Jul 2015
x = [2012 1 2; 2012 3 3; 2013 3 3];
d = datenum(x);
out = d - datenum(year(d),1,1) + 1;
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Sergey Kostrukov
on 12 Feb 2022
Edited: Sergey Kostrukov
on 12 Feb 2022
Fractional value of days since biginning of the year (0-364.9999):
daysFrac = days(currentTime - datetime(year(currentTime), 1, 1, TimeZone=currentTime.TimeZone))
To get the whole number starting from 1 (i.e. day index):
floor(daysFrac + 1)
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