How can I remove a variable from the parent workspace while a function is using it?
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I work with fairly large datasets, so the fact that they get duplicated when a function accepts them as an input can be a problem given 32bit memory constraints.
I have started using scripts instead of functions in order to save on memory usage, but this has caused additional problems, because now their is no distinction between the workspaces and I have to be very careful not to overwrite utility variables (such as x, y, t, n, etc.)
I would really like to pass a variable as a function input such that there are not two copies floating around the system.
How can I remove the variable from the parent workspace (or possibly act directly on only the parent workspace variables that are specified as functional inputs?)
Thanks, Sean
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Accepted Answer
the cyclist
on 14 Dec 2011
Are you changing the value of the variable after it is passed in? If not, then a copy is never made.
If it is changed, you could define the variable as global to ensure having only one copy.
3 Comments
Walter Roberson
on 14 Dec 2011
The only variables that can be overwritten are the ones that are initialized before the nested routines are declared.
function parent
shared1=[];
function nested1
shared1='hello'; %affects shared variable
i=15; %local variable because it was not initialized before nested routine
end
i=32; %local variable because it was not initialized before nested routine
nested1(); %will affect shared1 but not i
end
More Answers (1)
Walter Roberson
on 14 Dec 2011
To answer the original question:
evalin('caller', ['clear ', inputname(3)])
where the 3 here should be changed to the parameter number of the variable in the calling sequence.
Crashes due to doing this would not surprise me.
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