Gerchberg–Saxton algorithm

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maria
maria on 27 Sep 2015
Commented: Isaac Oguntoye on 31 May 2018
Hello! I have the following code:
for k=1:1:20;
G_pr=absP.*exp(i.*theta);
g_pr=ifft2(ifftshift(G_pr));
absPhase=abs(angle(g_pr));
maxPh=max(max(absPhase));
minPh=min(min(absPhase));
g_pr(absPhase>=(minPh+0.2*(maxPh-minPh)))=0;
g_pr=real(g_pr);
gg=255*g_pr/(max(max(g_pr)));
figure(1),imshow(uint8(gg)); title(num2str(k))
G=fftshift(fft2(g_pr));
G=G./abs(G);
theta=angle(G);
end
The first theta is the phase of my model image (angle(model)) However, this code diverges instead of converge, Does someone knows why?
Thank you
  2 Comments
Image Analyst
Image Analyst on 27 Sep 2015
You haven't given us enough code to even run your snippet that you posted here. Can't you step through it with the debugger to find out why?
maria
maria on 28 Sep 2015
Gerchberg–Saxton algorithm is made in four steps:
  • step 1: Fourier transform of the model
  • step 2: Replace the modulus of the model-FT by the signal acquired
  • step 3: Fourier-inverse step 2
  • step 4: Create a new model with modulus of the FT-signal and the phase is step 3. Am I right?Since yesterday I have simplified a lot my code to find the mistake. So now it looks like:
model=zeros(150);
model(5:20, 20:121)=1;
model(24:140, 40:50)=1;
model(24:140, 85:97)=1;
figure(1);imagesc(model); colormap(gray)
DS=model;
model=2*pi.*rand(150)-pi;
pi_signal=double(imread('pi.bmp'));
pi_signal=rgb2gray(pi_signal);
pi_signal=imresize(pi_signal, [150 150]);
j=fftshift(fft2(pi_signal));
j=abs(j)/(max(max(abs(j))));
j=imadjust(abs(j), [0; 0.01], [0; 1]);
%
for k=1:1:150;
step1=fftshift(fft2(model));
phase=angle(step1);
Gu=medfilt2(j).*exp(i*phase);
gx=fft2(fftshift(Gu));
model=pi_signal.*exp(i*angle(gx));
figure(7),imagesc(abs(gx)); colormap(gray), title(num2str(k));
end
where "model" is the model in step 1, "pi_signal" is the Fourier Transform of my signal and "j" is my signal.

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Accepted Answer

PNZ BDCB
PNZ BDCB on 25 Oct 2017
I'm not sure where in your code is the error. The following code works perfectly for me (adopted from wikipedia):
A = fftshift(ifft2(fftshift(Target)));
for i=1:25
B = abs(Source) .* exp(1i*angle(A));
C = fftshift(fft2(fftshift(B)));
D = abs(Target) .* exp(1i*angle(C));
A = fftshift(ifft2(fftshift(D)));
imagesc(abs(C)) %Present current pattern
title(sprintf('%d',i));
pause(0.5)
end
Before running the code, make sure 'Source' contains your input beam, for example:
Source = exp(-1/2*(xx0.^2+yy0.^2)/sigma^2);
And 'Target' contains your requested pattern.
The phase mask can be presented at the end of the for loop:
imagesc(angle(A))
  1 Comment
Isaac Oguntoye
Isaac Oguntoye on 31 May 2018
Thanks for the response. Did you consider using your code for a simple image like a dot? Thanks.

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