2nd Order Ordinary Differential Equation
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How do you solve the following 2nd order ODE
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/152727/image.jpeg)
so this question describes the motion of an object in 3-D space
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/152728/image.jpeg)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/152729/image.jpeg)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/152730/image.jpeg)
r vector represents the position of an object a vector is an acceleration vector caused by drag g vector simply represents the gravitational acceleration where g_z = -9.8
r(0) is given by
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/152731/image.jpeg)
and r'(0) or v(0) is given by
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/152732/image.jpeg)
* Now here is my question *
Assuming that drag is 0 (thus, a vector simply reduces to 0) and given initial conditions above
How can you find the time(t_I) at which the object hits the ground (r = 0)
and how can you express the position and velocity of this object as functions of time?
Can anyone provide the MATLAB code to solve these problems?? :P
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Answers (1)
Torsten
on 18 Dec 2015
If the drag is zero, the general solution is
x(t) = x(0) + vx(0)*t + gx/2*t^2
y(t) = y(0) + vy(0)*t + gy/2*t^2
z(t) = z(0) + vz(0)*t + gz/2*t^2
Best wishes
Torsten.
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