Error "Matrix index is out of range for deletion" with dynamic variable names but not hardcoded names?
1 view (last 30 days)
Show older comments
I get the error for the following case using dynamic variables:
% some things I pulled out of my data for the example:
arms = {'L','R'};
fields.L = [17 8 12 16];
fields.R = [12,6];
[~,removeL,removeR] = intersect(fields.L,fields.R);
uniquefields = fields;
% loop through arms (errors here)
for iArm = 1:length(arms)
uniquefields.(arms{iArm})(['remove',arms{iArm}]) = [];
end
But it doesn't happen when I hardcode it:
uniquefields.L(removeL) = [];
uniquefields.R(removeR) = [];
Does anyone know how to fix it? Thanks for any help!
0 Comments
Accepted Answer
Philip Borghesani
on 29 Jan 2016
The code blocks are not doing the same thing. Your loop is doing:
uniquefields.('L')('removeL') = []
It could be fixed with an eval of the string but that is going in the wrong direction. I suggest trying this sequence:
arms = {'L','R'};
fields.L = [17 8 12 16];
fields.R = [12,6];
[~,remove{1},remove{2}] = intersect(fields.L,fields.R);
uniquefields = fields;
% loop through arms
for iArm = 1:length(arms)
uniquefields.(arms{iArm})(remove{iArm}) = [];
end
There are probably much better solutions for your final code I don't much like needing a list of field names to be used dynamically.
More Answers (0)
See Also
Categories
Find more on Matrix Indexing in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!