Clear Filters
Clear Filters

How to smooth the edges

49 views (last 30 days)
Younes Nejahi
Younes Nejahi on 17 Feb 2016
Here is the original picture
I have and I need to smooth edges and get something more like this.
I tried many methods but neither gives me a smooth shape like this.
Anyone else have any idea how to approach this kind of problem?
Thanks in advance.
  2 Comments
Image Analyst
Image Analyst on 17 Feb 2016
Huh? Your "this" looks way more craggy and jagged and tortuous than the "original picture". Did you reverse them?
Younes Nejahi
Younes Nejahi on 18 Feb 2016
Yes, sorry I didn't realize I messed it up. I've fixed the images.

Sign in to comment.

Accepted Answer

Image Analyst
Image Analyst on 17 Feb 2016
Edited: Image Analyst on 17 Feb 2016
Assuming you reverses your original and output images, I'd start with the one with craggy arms and do an morphological opening on it with imopen(). then, if it's still not smooth enough and you know what you want one smooth curve from top to bottom, I'd use find() to get the edge column and use conv() or sgolayfilt() to smooth the edge to a nice slowly varying curve. Or you could use polyfit() if you want a global curve rather than a locally varying one.
  8 Comments
Image Analyst
Image Analyst on 26 Jul 2022
@Francesco Pignatelli the "other issue" should be discussed in a new discussion thread, not here in @Younes Nejahi's question. Attach your original image there (not here) and code for getting the edges. Chances are, you got the edges incorrectly (like using edge function instead of the bwboundary function).
Francesco Pignatelli
Francesco Pignatelli on 26 Jul 2022
@Image Analyst you are right. I made a new question:
https://se.mathworks.com/matlabcentral/answers/1767990-make-a-continuous-line-from-an-edge

Sign in to comment.

More Answers (1)

Brattv
Brattv on 17 Feb 2016
Hi,
Did you try to convert to gray and use imgaussfilt?
G = imread('YourImage.png');
grayIm = rgb2gray(G);
test = imgaussfilt(grayIm,4);
imshow(test)
The last parameter in imgaussfilt is the standard deviation. The higher the more blurred.
  1 Comment
Younes Nejahi
Younes Nejahi on 18 Feb 2016
Thanks for your response, but I meant the other way. I reversed the pictures.

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!