When with rounding and precision

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I am calculating the following: p15 = 0.8683*1.15
When I round to 5 decimal places round(p15,5) the answer is 0.99854 since Matlab sees full precision as 0.9985449999999999.
You can confirm this by typing sprintf('%1.30f',.8683*1.15)
ans = 0.998544999999999900000000000000
Unfortunately, I need to match the output of a standard calculator (don't ask why) and need to have the output as 0.99855. How is this possible via Matlab?

Accepted Answer

Walter Roberson
Walter Roberson on 19 Feb 2016
round(p15 * 1e6)/1e6
By the way, you cannot see the full precision on MS Windows by using sprintf(), but you can on OS-X
0.99854499999999990489385481851059012115001678466796875

More Answers (1)

MHN
MHN on 18 Feb 2016
What you said is not true! for multiplication the exact number is : 0.998545000000000
p15 = 0.8683*1.15;
r = round(p15,5);
then p15 = 0.998545000000000 and r = 0.998550000000000.
  5 Comments
MHN
MHN on 19 Feb 2016
I did not mean that there is a "problem" in sprintf. I meant even when we just assign a value like a=0.1; and then we use sprintf('%1.50f',a) the exact value is not 0.1. So, as long as one use sprintf and the floating point system, it will not get the result 0.100000000000000000000000000000000000000000.

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