Please I need help in MATLAB!!

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Samira Zeinab
Samira Zeinab on 25 Oct 2016
Commented: xiexiezaijian on 26 Oct 2016
I have to write a function that changes binary numbers to decimal numbers without using loops and without using the function bin2dec.
  1 Comment
Adam
Adam on 25 Oct 2016
If you have to write the function then write it. Then come and ask for help once you have made some effort.

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Answers (2)

xiexiezaijian
xiexiezaijian on 25 Oct 2016
since no loops and no bin2dec, this work could be done using the definition of binary number and vecterization operation. Take binary number 101 for example:
a = 101;
b = str2num(num2str(a)');
c = 2.^(2:-1:0)*b;%get the decimal number here
it is easy to handle the binary number with 4 or more digits and even numbers with points.
It seems that this is a question in MATLAB Cody.....
  2 Comments
Samira Zeinab
Samira Zeinab on 25 Oct 2016
I cannot use str2num . I have to use the point-wise operator :^ (dot ^ ) and the matrix multiplication operator applied to vectors. In particular, if u is a 1 by n vector and v is an n by 1 vector, then u v is the scalar given by u v = Σn i=1 u(i) v(i).)
xiexiezaijian
xiexiezaijian on 26 Oct 2016
If no str2num......maybe you could do like this;
a = 101;
b = num2str(101) - '0';% since '1'-'0' = 1;
c = 2.^(2:-1:0)*b';
really like a Cody problem....

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Walter Roberson
Walter Roberson on 25 Oct 2016
Hint: 2 to the 0, 2 to the 1, 2 to the 2, 2 to the 3... is 2 to the vector 0:3. Multiply each of those by the corresponding digit of the input and add the results

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