How to isolate two variables, Vout and Vin to obtain transfer function
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Hi this is my following code:
syms Vg Vin Vout Rs ro Rd CGS CGD CDB CL s gm;
eq1 = ((Vg-Vin)/Rs) + Vg*s*CGS + (Vg-Vout)*s*CGD == 0;
eq2 = gm*Vg + Vout/Rd + Vout/ro + Vout*s*CDB + Vout*s*CL + s*CGD*(Vout-Vg) == 0;
solVg = solve(eq2,Vg);
eq3 = ((solVg-Vin)/Rs) + solVg*s*CGS + (solVg-Vout)*s*CGD == 0;
So at this point, I have Vg in terms of, Vout and Vin. I'm having difficulty isolating the two variables, Vout and Vin to have the following transfer function: Vout/Vin.
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Accepted Answer
Star Strider
on 22 Nov 2016
You need to solve for ‘Vout’ first, then divide that expression by ‘Vin’:
Vout = solve(eq3, Vout);
H = Vout/Vin
[Hn, Hd] = numden(H);
Hn = collect(Hn, s)
Hd = collect(Hd, s)
with ‘H’ being your transfer function, ‘Hn’ is the numerator, ‘Hd’ the denominator:
H =
-1/(Rs*(CGD*s*((CDB*s + CGD*s + CL*s + 1/Rd + 1/ro)/(gm - CGD*s) + 1) + (CDB*s + CGD*s + CL*s + 1/Rd + 1/ro)/(Rs*(gm - CGD*s)) + (CGS*s*(CDB*s + CGD*s + CL*s + 1/Rd + 1/ro))/(gm - CGD*s)))
Hn =
(CGD*Rd*ro)*s - Rd*gm*ro
Hd =
(CDB*CGD*Rd*Rs*ro + CDB*CGS*Rd*Rs*ro + CGD*CGS*Rd*Rs*ro + CGD*CL*Rd*Rs*ro + CGS*CL*Rd*Rs*ro)*s^2 + (CGD*Rd*Rs + CGS*Rd*Rs + CDB*Rd*ro + CGD*Rd*ro + CL*Rd*ro + CGD*Rs*ro + CGS*Rs*ro + CGD*Rd*Rs*gm*ro)*s + Rd + ro
2 Comments
Star Strider
on 22 Nov 2016
My pleasure!
I use the Symbolic Math Toolbox extensively in circuit design and analysis.
More Answers (1)
Walter Roberson
on 21 Nov 2016
solVin = solve(eq3, Vin);
Vin_over_Vout = simplify( expand( SolVin/Vout ) );
2 Comments
Walter Roberson
on 22 Nov 2016
Opps, yes, I did Vin/Vout instead of Vout/Vin, but you can use
Vout_over_Vin = simplify( expand( Vout/SolVin ) );
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