FFT of a Signal

11 views (last 30 days)
Harry
Harry on 26 Feb 2017
Commented: Star Strider on 27 Feb 2017
Hi, I would like to take the FFT of a signal but for some reason I do something wrong.
May someone could help me out?
I would like to see the FFT Spectrum for 2 seconds.
I attached the Excel file and the code.
Thanks!

Accepted Answer

Star Strider
Star Strider on 26 Feb 2017
The constant (‘direct current’ or ‘d-c’ 0 Hz) offset is hiding the rest of your spectrum. This is a common problem, and since removing the constant offset does not affect the rest of your signal (and you can easily recover it if needed, since it is the mean of your signal), remove it before calculating the fft to see the rest of your spectrum.
This works:
[d,s] = xlsread('Good State.xls');
Time = d(:,1);
Good = d(:,2);
L = size(d,1); % Vector Length
Ts = mean(diff(Time)); % Sampling Interval (Assume ‘seconds’)
Fs = 1/Ts; % Sampling Frequency (Assume ‘Hz’)
Fn = Fs/2; % Nyquist Frequency (Assume ‘Hz’)
Good = Good - mean(Good); % Remove D-C (Constant) Offset
Y = fft(Good)/L; % Scaled Two-Sided Discrete Fourier Transform
Fv = linspace(0, 1, fix(L/2)+1)*Fn; % Frequency Vector
Iv = 1:length(Fv); % Index Vector For Plot
figure(1)
plot(Fv, 2*abs(Y(Iv)))
grid
xlabel('Frequency')
ylabel('Magnitude')

More Answers (1)

Harry
Harry on 26 Feb 2017
Brilliant! Thank you!
  5 Comments
Harry
Harry on 27 Feb 2017
Nice one!
Much appreciated!
Thank you
Star Strider
Star Strider on 27 Feb 2017
My pleasure!

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!