Removing rows that are not unique from an array?

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Is there an easy way to remove ALL rows that are NOT unique? For example, how would I get B from A?
A = [1 2; 1 3; 1 4; 1 2; 1 5];
B = [1 3; 1 4; 1 5];
I could do this in a loop, but there seems like there must be a more elegant way. I've looked at various applications in the forum using the unique() function, but a solution is not obvious to me.
Thanks!

Accepted Answer

Star Strider
Star Strider on 7 Jul 2017
This works:
A = [1 2; 1 3; 1 4; 1 2; 1 5];
[~,ia,ic] = unique(A, 'rows'); % Unique Elements
v = accumarray(ic, 1); % Tally Occurrences Of Rows
B = A(ia(v==1),:) % Keep Rows That Only Appear Once
B =
1 3
1 4
1 5
  5 Comments
John Jendzurski
John Jendzurski on 8 Jul 2017
Thank you, Star Strider. This looks perfect. I was not aware of the accumarray() function...until now!

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More Answers (1)

Jan
Jan on 7 Jul 2017
Edited: Jan on 8 Jul 2017
As = sortrows(A);
k = find([true; any(diff(As, 1, 1), 2); true]);
B = As(k(diff(k) == 1), :);
And if the original order is wanted:
[As, idx1] = sortrows(A);
k = find([true; any(diff(As, 1, 1), 2); true]);
idx2 = k(diff(k) == 1);
B = A(idx1(idx2), :);
For A = randi([1, 20], 1e5, 4) the first method is 15% faster than the unique/accumarray method.
  3 Comments
Image Analyst
Image Analyst on 8 Jul 2017
This is asked so often it should be in the FAQ. But before I do, I'd like to have a solution to the other case people ask a lot about, and that is where people want to keep the first instance of the duplicate row (along with unique rows), rather than toss out all rows that are members of duplicates. Another case might be to keep only the duplicate rows.
Jan
Jan on 8 Jul 2017
Edited: Jan on 8 Jul 2017
Isn't "keeping the first instance" solved by
unique(A, 'rows', 'first')
And for keeping the multiple occuring rows only use:
As = sortrows(A);
k = find([true; any(diff(As, 1, 1), 2); true]);
B = As(k(diff(k) > 1), :);
% ^ instead of ==

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