how to use""\langle〈 and \rangle 〉 "" in matlab?

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the function is used to convert the binary sequence into 24 integers in which each one is produced by 8 binary bits.
  2 Comments
Jan
Jan on 31 Jan 2018
Please explain, in which format the input "binary sequence" is available.
PLACEIUS NISHIGA G
PLACEIUS NISHIGA G on 31 Jan 2018
sir ,I write a code but the final ans E contain two different matrix array size that is the combination of both E2 and k2 .I cannot convert into a single binary matrix. The binary sequence is converted into 24 integers in which each one is produced by 8 binary bits.please execute the code and if you find any different idea please inform me as soon as possible.
if true
clc;
clear all;
close all;
img = imread('cameraman.tif');
c=img';
d=c(:);
[W,L]=size(img);
k=randi(192,1,192);
syms k1 t
for i=1:4
k1=k(((48*i)-47):(48*i));
a1 = symsum(k1*(2^(t-(48*i)+47)),t,((48*i)-47),(48*i));
a=a1/(2^48);
end
for x=1:2
r(x)=mod(prod(a*(2^48)+a(x)),0.4)+3.6;
C(x)=mod(prod(a*(2^48)+a(x+2)),1);
end
C1=C(1);
C2=C(2);
for y=1:[W,L]
if y==1
C(y)=C(x);
else
if y~=1&&C(y-1)<0.5
C(y)=0.5*(r(x)*C(y-1));
else
if y~=1&&C(y-1)>=0.5
C(y)=0.5*(r(x)*(1-(C(y-1))));
end
end
end
end
for y=1:[W,L]
if y==1
E1(y)=d(y);
else
E1(y)=mod(d(y)+floor(C(y)*(10^13))+d(y-1),256);
end
end
for y=1:[W,L]
if y==[W,L]
E2(y)=E1(y);
else
E2(y)=mod(E1(y)+floor(C(y)*(10^13))+E1(y+1),256);
end
end
E2=E2';
Q=sum(E2');
Q=sym2poly(Q);
for j=1:192
q=dec2bin(Q,j);
kb=dec2bin(k,j);
end
kb = kb(randi(size(kb,1)),:);
k2=xor(q,kb);
E=[1,(W*L)+24];
E={k2,E2}
%E=bin2dec(char('0'+reshape(bits, 8, 24).'))
end

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Accepted Answer

Walter Roberson
Walter Roberson on 31 Jan 2018
bin2dec(char('0'+reshape(bits, 8, 24).'))
... but what does this have to do with the angle brackets?

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