Why does the second example fail?
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Derrick Salmon
on 13 Feb 2018
Commented: Derrick Salmon
on 14 Feb 2018
here's my code and the response
testvec = [Xc,Yc,sig,A]
ErrTest1 = RMS_Err_func(Image,Xc,Yc,sig,A)
ErrTest2 = RMS_Err_func(Image,testvec)
gives:
ErrTest1 =
0.0942
Not enough input arguments.
Error in NM_2D_Gauss_fit>RMS_Err_func (line 60)
r(l,m) = sqrt((l-Xc).^2+(m-Yc).^2);
Error in NM_2D_Gauss_fit (line 46)
ErrTest2 = RMS_Err_func(Image,testvec)
3 Comments
Walter Roberson
on 13 Feb 2018
... Yes?
You are passing it in to the function, so the second argument can examine the contents of testvec.
Accepted Answer
Walter Roberson
on 13 Feb 2018
I suspect that your testvec is a vector that has within it values for Xc, Yc, sig, A . If so then,
temp = num2cell(testvec);
ErrTest2 = RMS_Err_funct(Image, temp{:});
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