Why does the second example fail?

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here's my code and the response
testvec = [Xc,Yc,sig,A]
ErrTest1 = RMS_Err_func(Image,Xc,Yc,sig,A)
ErrTest2 = RMS_Err_func(Image,testvec)
gives:
ErrTest1 =
0.0942
Not enough input arguments.
Error in NM_2D_Gauss_fit>RMS_Err_func (line 60)
r(l,m) = sqrt((l-Xc).^2+(m-Yc).^2);
Error in NM_2D_Gauss_fit (line 46)
ErrTest2 = RMS_Err_func(Image,testvec)
  3 Comments
Derrick Salmon
Derrick Salmon on 13 Feb 2018
Walter
Is there no way for the function so see the contents of testvec?
Walter Roberson
Walter Roberson on 13 Feb 2018
... Yes?
You are passing it in to the function, so the second argument can examine the contents of testvec.

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Accepted Answer

Walter Roberson
Walter Roberson on 13 Feb 2018
I suspect that your testvec is a vector that has within it values for Xc, Yc, sig, A . If so then,
temp = num2cell(testvec);
ErrTest2 = RMS_Err_funct(Image, temp{:});

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