Change one element in a row at a time with an uniform probability.

Hello! I want to change one element in a row of my matrix at a time with uniform probability. Currenty my matrix of [50*50] chooses one element at a time from a set of [0, 0.1, 0. 0.2, 0.3, 0.4] with an uniform probability. With the following code. But in this more than one element changes at a time which does not satisfy the above condition. How to satisfy changing one element at a time with an uniform probablility?

    % code
    value_set = [range];
    numvalues = 50;
    x_star = value_set(randi(numel(value_set), 1, numvalues));

Answer 1

[BhaTTa]

Hey @Neje, i assume that in the given matrix you have to randomly chose a cell and replace that with a single element from the set of [0,0.1,0.2,0.3,0,4] with uniform probability

Please refer to the below code for the implementation.

value_set = [0, 0.1, 0.2, 0.3, 0.4];

matrix = zeros(50, 50);

num_updates = 100;

for i = 1:num_updates

row = randi(50);

col = randi(50);

new_value = value_set(randi(numel(value_set)));

% Update the selected element in the matrix

matrix(row, col) = new_value;

disp(matrix); % display each time so that we can see that only one cell is changing in each loop.

end

disp(matrix);

Hope it helps.