How to delete consecutive values in a vector and to save the central one?

I have a vector of increasing values. I want to create a second vector that contains all the "single" numbers and, if I have consecutive numbers, contains only the central value (rounded down, if it is the case).

For example, if I have the vector a=[10 15 16 17 18 19 31 32 37], the final vector should be b=[10 17 31 37].

Unluckily I am not able to find a way to solve this problem. Any ideas?

Thank you in advance for your help.

Answer 1

[Image Analyst]

Sounds like homework but since you didn't tag it as homework, here's my solution:

a=[10 15 16 17 18 19 31 32 37]
da = [2, diff(a)]
startingIndexes = [find(da ~= 1), length(da)+1]
groupIndex = 1;
for k = 1 : length(startingIndexes)-1
  index1 = startingIndexes(k);
  index2 = startingIndexes(k+1) - 1;
  output(groupIndex) = floor(median(a(index1 : index2))); % Get median of this group.
  groupIndex = groupIndex + 1;
end
output

I'm sure there are other ways, perhaps more compact and cryptic, but this seems intuitive and easy for a beginner to follow.

[CaG]

Thank you! It works fine.