How can we get the solution for an 'exact differential equation' dy/dx=(x^2-y^2)/2*x*y in matlab
26 views (last 30 days)
Show older comments
'exact differential equation'dy/dx=(x^2-y^2)/2*x*y'
2 Comments
Star Strider
on 30 Sep 2018
You seem to have omitted the LHS.
dxdt = (x^2-y^2)/2*x*y
dydt = (x^2-y^2)/2*x*y
dxdy = (x^2-y^2)/2*x*y
dydx = (x^2-y^2)/2*x*y
or something else?
Accepted Answer
More Answers (0)
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!