splitting the date in the same line to three variables

Hi,

I am trying to split the date in the same line but still stuggling. Any ideas?

here is my hint:

Thanks!

start_date=20110101
start_date,['%4d',repmat('%2d',1,2)],'start_year','start_month','start_day');

so the result should be:

start_year=2011

start_month=01

start_day=01

[Geoff Hayes]

sensation - what are you trying to do with that second line of code? Is there a particular function that you are calling since there is a trailing ')'? Should your start_year, start_month and start_day be strings or integers (note if integers, you won't be able to prefix it with a zero). Please clarify.

[sensation]

Hi Geoff. They should be string. thanks!

Answer 1

[Star Strider]

Try this:

start_date=20110101;
dva = datevec(num2str(start_date,'%8d'), 'yyyymmdd')
start_year = dva(1)
start_month = dva(2)
start_day = dva(3)

producing:

start_year =
        2011

start_month =
     1

start_day =
     1

Answer 2

[Peter Perkins]

Depe3nding on whether you have numeric (ads in your OP) or text (as in your comment):

>> start_date = 20110101;
>> d = datetime(start_date,'ConvertFrom','yyyymmdd')
d = 
  datetime
   01-Jan-2011 00:00:00
>> start_date = '20110101';
>> d = datetime(start_date,'InputFormat','yyyyMMdd')
d = 
  datetime
   01-Jan-2011  

Not sure why you need to then split this up, you likely do not need to. But if you insist:

>> [yr,mo,day] = ymd(d)
yr =
        2011
mo =
     1
day =
     1