Asked by Nikolaos Zafirakis
on 30 Apr 2019

I have a for loop and some challenging mathematical equations my goal is to get a 3x3 matrix where A is preferable I would like to make A1 A2 cell matrices and collect the values leading to an easy final equation. Thanks in advance for anyone that helps me out!

for i = 1:100;

v2(1:3,i) = [cross(v1(1:3,i),(Sb(1:3,i)))/norm(cross(v1(1:3,i),(Sb(1:3,i))))]; % Works 3x1

w2(1:3,i) = [cross(w1(1:3,i),(Bb(1:3,i)))/norm(cross(w1(1:3,i),(Bb(1:3,i))))]; % Works 3x1

v3(1:3,i) = cross(v1(1:3,i),v2(1:3,i)); % Works 3x1

w3(1:3,i) = cross(w1(1:3,i),w2(1:3,i)); % Works 3x1

A1 = transpose([v1(1:3,i),v2(1:3,i),v3(1:3,i)]); % Works but donsn't store values 3x3

A2 = [w1(1:3,i),w2(1:3,i),w3(1:3,i)]; % Works but donsn't store values 3x3

A = mtimes(A1,A2); % Not working 3x3

end

Answer by KSSV
on 30 Apr 2019

Edited by KSSV
on 30 Apr 2019

Accepted Answer

A1 = zeros(3,3,100) ;

A2 = zeros(3,3,100) ;

A = zeros(3,3,100) ;

for i = 1:100;

v2(1:3,i) = [cross(v1(1:3,i),(Sb(1:3,i)))/norm(cross(v1(1:3,i),(Sb(1:3,i))))]; % Works 3x1

w2(1:3,i) = [cross(w1(1:3,i),(Bb(1:3,i)))/norm(cross(w1(1:3,i),(Bb(1:3,i))))]; % Works 3x1

v3(1:3,i) = cross(v1(1:3,i),v2(1:3,i)); % Works 3x1

w3(1:3,i) = cross(w1(1:3,i),w2(1:3,i)); % Works 3x1

A1(:,:,i) = transpose([v1(1:3,i),v2(1:3,i),v3(1:3,i)]); % Works but donsn't store values 3x3

A2(:,:,i) = [w1(1:3,i),w2(1:3,i),w3(1:3,i)]; % Works but donsn't store values 3x3

A(:,:,i) = mtimes(A1,A2); % Not working 3x3

end

Nikolaos Zafirakis
on 30 Apr 2019

KSSV
on 30 Apr 2019

Edited

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