can you write a vector function?

271 views (last 30 days)
I am looking to express a parametrized vector function and draw the surface..
  2 Comments
Adam Danz
Adam Danz on 23 Jun 2019
How can we help you with that? Where are you stuck?
Thomas Starai
Thomas Starai on 23 Jun 2019
What is the syntax for something like:
x(u,v) = ( 2-v*sin(u/2)*sin(u), 2-v*sin(u/2)*cos(u), v*cos(u/2) )
?

Sign in to comment.

Accepted Answer

Star Strider
Star Strider on 24 Jun 2019
You pretty much wrote it yourself:
x = @(u,v) [2-v.*sin(u/2).*sin(u); 2-v.*sin(u/2).*cos(u); v.*cos(u/2)];
See the documentation sections on Anonymous Functions (link) and Vectorization (link) for an extended discussion of both. The documentation for the ndgrid (link) function will also be helpful.
  4 Comments
Thomas Starai
Thomas Starai on 24 Jun 2019
Symbolic math is intriging.....efficiency is not an issue.
After looking at anonymous functions, I fail to see why you couldn't just define a function without the @ operator. Can you provided some insigh as to why this is necessary?
Star Strider
Star Strider on 24 Jun 2019
The @ operator denotes a function handle, and is necessary if you want to define it as an anonymous function. You could define it as a function file, however that is usually reserved for more complicated functions. See Function Basics for details.
You don’t have to define it as a function if you don’t want to — it will simply execute as a statement instead, although you could not then use it as a function later in your code — however in your original Question you specified that it is a function. See What Is a Function Handle? for an extended discussion.

Sign in to comment.

More Answers (1)

Ali Zain
Ali Zain on 6 Jan 2020
y= function(t)=[0.2582;
-0.3631 cos(0.21910*(t);
0.3572 cos(0.4158)(t);
0.3473*cos(0.6180t);
0.3336*cos(0.8135t);
0.3162*cos(t);
0.2954*cos(1.1756t);
0.2714*cos(1.3383t);
0.2443*cos(1.4863t);
0.2146*cos(1.6180t);
0.1826*cos(1.7321t);
0.1485*cos(1.8271t);
0.1128*cos(1.902t);
-0.0759*cos(1.9563t);
0.0382*cos(1.9890t)]
why it is giving error...
  1 Comment
Star Strider
Star Strider on 6 Jan 2020
Except for the second line, there is no multiplication operator.

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!