How do I remove leading characters from a string?
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pruth
on 18 Sep 2019
Commented: Walter Roberson
on 19 Sep 2019
I read one ascii file. and created this dummy mat file (attached ).
To make simple matrix out of it i need to split the string
i used this code (below) but it coudnt split the first string which is a date and time with some leading number since there is no space in between. There is this number before the date and time, i want remove those numbers so can use datenum on that string !
for i = 1:len_data
segments = regexp(dummy{1,1}{i,1},' ', 'split');
end
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Accepted Answer
Walter Roberson
on 18 Sep 2019
segments = regexp(dummy{1,1}{i,1}, '\t', 'split');
Perhaps you could have used readtable() on the ascii file: it would likely have detected the tab delimiter.
3 Comments
Walter Roberson
on 18 Sep 2019
strjoin(segments(2:3), ' ')
Note that we no longer recommend using datenum: we recommend using datetime()
More Answers (1)
Ankit
on 18 Sep 2019
Hello Pruth,
a = extractBetween(dummy{1, 1}, 10,20)
where 10 is the start position and 20 is the end position.
Cheers
Ankit
3 Comments
Ankit
on 18 Sep 2019
hello pruth,
cell data can be converted to double using str2double. But you can't use it to convert date, it will return a NaN value.
thanks
Ankit
Walter Roberson
on 19 Sep 2019
However, datetime() is happy to process cell array of character vectors ;-)
Also, in newer releases, duration() is happy to process cell array of character vectors. This was not possible in older releases.
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