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I am new to MatLab and still learning how to use 'for' loops correctly, as I may not even need to use one here.

I am trying to set up a coordinate system which will then cycle through every point and find the distance. I have coded the coordinate system like so:

x_step = 0.01;

z_step = 0.02;

Z = (-5:z_step:5);

X = (0:x_step:5);

which leaves me with two vectors, both with dimensions of 1-by-501.

Now the equation I am using to calculate the response at some point in the coordinate space is:

How would I write code which tells me the distance at each point?

I have had a go at writing a simple for loop which just outputs one value which I assume is the last. Here is the code:

for i = X

for j = Z

R = sqrt(i.^2+j.^2);

end

end

Please, any tips/advice or help would be greatly appreciated! Thanks.

Alex Mcaulley
on 29 Oct 2019

Using for loops:

R = zeros(numel(X),numel(Z));

for i = X

for j = Z

R(i,j) = sqrt(i.^2+j.^2);

end

end

Alex Mcaulley
on 29 Oct 2019

Then, the solution should be:

x_step = 0.01;

z_step = 0.02;

Z = (-5:z_step:5);

X = (0:x_step:5);

R = zeros(numel(X),numel(Z));

for i = 1:numel(X)

for j = 1:numel(Z)

R(i,j) = sqrt(X(i).^2+Z(j).^2);

end

end

Or a better solution:

x_step = 0.01;

z_step = 0.02;

Z = (-5:z_step:5);

X = (0:x_step:5);

[Z,X] = meshgrid(Z,X);

R = sqrt(X.^2+Z.^2);

And still better

x_step = 0.01;

z_step = 0.02;

Z = (-5:z_step:5);

X = (0:x_step:5);

R = sqrt(Z.^2+X'.^2);

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