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App designer: randomly generated sentence GUI

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Hello everyone,
I have created a random phrase generator in Matlab; it starts by choosing between two types of sentences (using randi) and then uses randi again to construct one of the two types and displays it in the command window.
I am having, however, hell of a time trying to create a GUI that displays the generated text somewhere. I added a callback to my random phrase generator function and associated it with a button and a textbox; the function runs properly when I press the button but nothing appears in the textbox.
Anyone knows?
I have been looking it up but it seems that the app designer has been changing every year.
  2 Comments
Mohammad Sami
Mohammad Sami on 26 Dec 2019
Can you provide a copy your callback function to see if anything is wrong with it.
Eleanna Kritikaki
Eleanna Kritikaki on 26 Dec 2019
Edited: Stephen23 on 26 Dec 2019
Yes, here it is below. Thing is i am not sure exactly where to copy and paste it and what I should modify etc, what to tie to what... I guess the button and the text box have to share the same callback etc.
% Random phrase generator
clear all;
clc;
% Choose between the two types
rng('shuffle')
Ch=randi(35);
if Ch==10
rng('shuffle')
Type_1 = {'phrase 1', 'phrase 2',.... 'phrase n'};
Nugget = [Type_1{randi(numel(Type_1))}];
fprintf(Nugget)
elseif Ch~=10
% Create 3 types of cells to put them in a cell array
Start = {'phrase 1 ','phrase 2 ','phrase 3 '...'phrase n'};
Middle = {'phrase 1 ','phrase 2 ','phrase 3 '...'phrase n'};
Final={'phrase 1 ','phrase 2','phrase 3 '...'phrase n '};
% Put them all in a cell array
A={Start,Middle,Final};
% Create variable with a combination of the three parts called 'Sentence'
rng('shuffle');
a=Start{randi(numel(Start))};
rng('shuffle');
b=Middle{randi(numel(Middle))};
rng('shuffle');
c=[Final{randi(numel(Final))} '.'];
Sentence = [a b c];
% Print this variable
fprintf(Sentence)
end

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Accepted Answer

Mohammad Sami
Mohammad Sami on 26 Dec 2019
If you are using app designer, to build your GUI you can do as follows.
Drag and drop a button and an "Edit Field (Text)" into your app.
If this is a blank app, the names would be Button and EditField.
Right click the button, goto callbacks and select Add ButtonPushedFcn callback.
The designer will switch to code view.
You can then simply put in your random generation code in the callback.
At the end just assign the Sentence output to the EditField as follows
function ButtonPushed(app, event)
% Your random sentence generator code here
% Sentence = ....
app.EditField.Value = Sentence;
end
This should update the edit field with a new sentence everytime you click the button.
  3 Comments
Image Analyst
Image Analyst on 26 Dec 2019
What is the name of your edit text box? Is it EditField? It's case sensitive so check that also.
Eleanna Kritikaki
Eleanna Kritikaki on 27 Dec 2019
So thanks Mohammad, this finally worked. However, as Image Analyst pointed out below, the 'clear all' command had to go.

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More Answers (1)

Image Analyst
Image Analyst on 26 Dec 2019
Edited: Image Analyst on 26 Dec 2019
Assuming your edit text box is named edtText, try this. First create your sentence however you do it, then:
app.edtText.String = yourSentence; % Set string property, not value property.
Also, your callback for the push button where you create this sentence and send it to the GUI should not have a "clear all" command in it.
  4 Comments
Eleanna Kritikaki
Eleanna Kritikaki on 27 Dec 2019
Hello!
I did try both- capital s as well as lower case s, and got the same message (I guess I erroneously copied and pasted the latter one). Apologies!
Mohammad Sami
Mohammad Sami on 30 Dec 2019
Good to hear that it works.
I did not notice the clear all.
The reason why it broke your code, is that it will clear the variables passed into your function (app and event). So you will no longer be able to access these variables in the later part of your function. In this case we needed the "app" variable to access the edit text field.

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