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Remove zeros from a 3D array

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Uerm
Uerm on 3 Feb 2020
Commented: Uerm on 10 Feb 2020
Hi,
I have a 3D array A = 90x38021x1633. The second dimension (38021) contains a lot of zeros as I have done zero padding before concatenating multiple 3D arrays to get A. How can I now remove these zeros such that B = 90xYx1633, where Y < 38021?
Thanks!

Accepted Answer

the cyclist
the cyclist on 3 Feb 2020
Edited: the cyclist on 3 Feb 2020
Do you mean you have "slices" of all zeros? Then this should work:
% Create an array like your A matrix, where some "slices" of data is all zeros
A = repmat([0 0 0 0; 1 0 0 0; 1 0 1 0],[1 1 5]);
% Find indices to slices in the 1-3 plane that have any non-zeros.
idx = any(A ~= 0,[1 3]);
% Create B from only the slices that have non-zeros
B = A(:,idx,:);
Just use your A, instead of the pretend one I made. Also, you can combine the two steps by just doing
B = A(:,any(A ~= 0,[1 3]),:);
but I wanted to call out explicitly what is going on.

More Answers (1)

Nils Speetzen
Nils Speetzen on 3 Feb 2020
Hi,
I assume you want to remove rows/planes containing only zeros. To find these, you can use
all(A==0, [1 3])
This searches for all planes where all entries along the first and third dimension are equal to zero.
To remove all those rows/planes, you can directly index A via this expression:
A(:,all(A==0, [1 3]),:) = []
I hope this helps!
  8 Comments
Uerm
Uerm on 10 Feb 2020
Thanks a lot for your help! It makes sense now.

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