Chebyshev Polynomial functions of the first kind
6 views (last 30 days)
Show older comments
function y = myChebyshevPoly1(n,x)
%y = myChebyshevPoly1(n,x)
%y is the vector for the first n Chebyshev numbers
if n == 0
out = 1; %first base case
else if n == 1
out = x; %second base case
else
out = 2*x*myChebyshevPoly1((n-1),x)-myChebyshevPoly1((n-2),x);%recursive call
end
end % end myChebyshevPoly1
>>x = myvec/26;
>> n = 5;
>> y = myChebyshevPoly1(n,x)
when i run it and apply the following commands it will appear as error can someone explain to me what am i doing wrong?
also how can i ensure that expression above works for the case when x is a vector.
0 Comments
Answers (1)
Patrick Gipper
on 14 Feb 2020
You just need to replace "out" with "y". Maybe you already caught this?
function y = myChebyshevPoly1(n,x)
%y = myChebyshevPoly1(n,x)
%y is the vector for the first n Chebyshev numbers
if n == 0
y = 1; %first base case
else if n == 1
y = x; %second base case
else
y = 2*x*myChebyshevPoly1((n-1),x)-myChebyshevPoly1((n-2),x);%recursive call
end
end % end myChebyshevPoly1
3 Comments
Patrick Gipper
on 14 Feb 2020
Oh right, I just used a scalar test case. One change fixes that.
function y = myChebyshevPoly1(n,x)
%y = myChebyshevPoly1(n,x)
%y is the vector for the first n Chebyshev numbers
if n == 0
y = 1; %first base case
else if n == 1
y = x; %second base case
else
y = 2*x.*myChebyshevPoly1((n-1),x)-myChebyshevPoly1((n-2),x);%recursive call
end
end % end myChebyshevPoly1
See Also
Categories
Find more on Startup and Shutdown in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!