the Jacobi Iterative method(urgent)

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Mahdi Almahuzi
Mahdi Almahuzi on 11 Apr 2020
Commented: Rik on 12 Apr 2020
hello , I have to Write a Matlab code to solve an n x n linear
system using the Jacobi Iterative method
I need this code to solve this problem
I wrote this code but it does not solve it correctly
A = [ 1 -1 2 -1 ;2 -2 3 -3;1 1 1 0;1 -1 4 3];
b = [-8; -20; -2; 4];
% error tolerance
tol =10^-3;
%initial guess:
x0 = zeros(4,1);
xnew=x0;
error=1;
while error>tol
xold=xnew;
for i=1:length(xnew)
off_diag = [1:i-1 i+1:length(xnew)];
xnew(i) = 1/A(i,i)*( b(i)-sum(A(i,off_diag)*xold(off_diag)) );
end
error=norm(xnew-xold)/norm(xnew);
end
x_jacobian=xnew
the answer must be like this
can anybody help me ( the deadline for this homework tomorrow)
  6 Comments
Torsten
Torsten on 11 Apr 2020
Did you change A and b to the data of your exercise ?
Rik
Rik on 12 Apr 2020
Your question is not urgent, the reason for that is explained here.
You can find guidelines for posting homework on this forum here.

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