# store variables in a for loop

10 views (last 30 days)
Davide Cerra on 21 Apr 2020
Commented: Sriram Tadavarty on 21 Apr 2020
Hello,
i m trying to obtain a set of coordinates for this:
function [x, y] = gencircle(xo,yo,r,N)
x=(xo+r*cos(theta))';
y=(yo+r*sin(theta))';
clear all
xo=[1 2 3 4 5 6 7 8];
yo=[-1 -0.5];
r=0.01;
N=10;
theta=2*pi/N*(1:N+1);
th=0.00235;
for j=1:length(yo)
for i=1:length(xo)
[xout(:,i), yout(:,j)]=gencircle(xo(i),yo(j),r,N)
[xin(:,i), yin(:,j)]=gencircle(xo(i),yo(j),r-th,N)
end
end
for j=1:length(yo)
for i=1:length(xo)
aa=[xout(:,i),yout(:,j)]
end
end
how can i store the vector aa for each loop?
Thanks

Sriram Tadavarty on 21 Apr 2020
Edited: Sriram Tadavarty on 21 Apr 2020
Hi Davide,
You can make the following modification to the code as shown below, which stores all the loop iteration values in the variable aa:
clear all
xo=[1 2 3 4 5 6 7 8];
yo=[-1 -0.5];
r=0.01;
N=10;
theta=2*pi/N*(1:N+1);
th=0.00235;
for j=1:length(yo)
for i=1:length(xo)
[xout(:,i), yout(:,j)]=gencircle(xo(i),yo(j),r,theta);
[xin(:,i), yin(:,j)]=gencircle(xo(i),yo(j),r-th,theta);
end
end
aa = zeros(size(xout,1),2,length(yo)*length(xo)); % Initialize the variable
tmp = 1;
for j=1:length(yo)
for i=1:length(xo)
aa(:,:,tmp)=[xout(:,i),yout(:,j)];
tmp = tmp+1;
end
end
% aa will be a variable of size length(xout) x 2 x (loop iterations)
% loop iterations here is equal to the product of length(yo) and length(xo) (implies 16)
% Each iteration value can be accessed by indexing from 3rd dimension,
% implies for example fifth iteration can be accessed with aa(:,:,5)
function [x, y] = gencircle(xo,yo,r,theta)
x=(xo+r*cos(theta))';
y=(yo+r*sin(theta))';
end
Hope this helps.
Regards,
Sriram
Sriram Tadavarty on 21 Apr 2020
Please do accept the answer, if helped

### Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!