MATLAB code for right handed circular polarization

Hello, I need help to write simple code that preview right handed circular polarization, using the cos and sin fun. also in the plot must see the direction of the polarization (for example with arrows).

the expression of RHCP is : Acos(t)+Asint(t)

[Walter Roberson]

To check: is Acos(t) to mean arccosine of t, or is it to mean A multiplied by cosine of t ? Is Asint intended to mean A times sine (of something?) times (t applied to t) ??

[Roman]

A*cos(t)+A*sin(t) A- is the amplitude of the sinus and cosine waves.

Answer 1

[Image Analyst]

You mean like this: ???

fontSize = 20;
A = 10; % Amplitude.
t = linspace(0, 2 * pi, 40);
signal = A .* cos(t) + A .* sin(t);
stem(t, signal, 'bo-', 'LineWidth', 2);
xlabel('t', 'FontSize', fontSize);
ylabel('signal', 'FontSize', fontSize);
title('RHCP', 'FontSize', fontSize);
grid on;
% Enlarge figure to full screen.
set(gcf, 'units','normalized','outerposition',[0 0 1 1]);
% Give a name to the title bar.
set(gcf,'name','Demo by ImageAnalyst','numbertitle','off')

[Walter Roberson]

A .* cos(t) + A .* sin(t) could be simplified to A .* (cos(t) + sin(t))

Answer 2

[Bjorn Gustavsson]

That it is possible to rewrite A*cos(t) + A*sin(t) to A*(cos(t)+sin(t)) clearly shows that that is a scalar quantity - such has by definition no polarization. Try instead with something that is a vector-valued function:

A*[cos(w*t-kz),-sin(w*t-k*z),0]

Answer 3

[AbdulRehman Khan Abkhan]

A = 10; % Amplitude.

t = linspace(0, 2 * pi, 40);

signal = A .* cos(t) + A .* sin(t);

stem(t, signal, 'bo-', 'LineWidth', 2);

x('t');

y('signal');

title('RHCP');

grid on;

% Enlarge figure to full screen.

set(gcf, 'units','normalized','outerposition',[0 0 1 1]);

% Give a name to the title bar.

set(gcf,'name','Demo by ImageAnalyst','numbertitle','off')

[Image Analyst]

How is your Answer different than mine?