# Force tiledlayout('flow') to layout vertically

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Scott on 16 Aug 2020
Answered: Dave B on 17 Mar 2023
The problem I have with tiledlayout('flow') is that it it will often end up arranging the plots in a 2x2 grid, rather than a 4x1.
I understand tiledlayout('flow') tries to keep a 4:3 ratio for plots, but this is not useful for my data.
Tiledlayout(x,1) won't work because I don't know x beforehand.
I had hoped that in the case of tiledlayout(x,1) I could set the GridSize property, but it is read only.
Any suggestions on how to overcome this would be helpful, thank you.

Dave B on 17 Mar 2023
Starting in R2023a you can use the 'horizontal' and 'vertical' tile arrangements to accomplish layouts that are dynamically sized but only in one direction. More information available in the tiledlayout documentation.
figure(1)
t=tiledlayout('horizontal');
nexttile
plot(rand(1,10))
nexttile
bar(rand(1,10))
nexttile
scatter(rand(1,10),rand(1,10)) figure(2)
t=tiledlayout('vertical');
nexttile
plot(rand(1,10))
nexttile
bar(rand(1,10))
nexttile
scatter(rand(1,10),rand(1,10)) Srivardhan Gadila on 20 Aug 2020
Based on the above information and the documentation of tiledlayout & nexttile, for this particular problem you can make use of the 'nexttile(span)' syntax as follows:
% Let the max number tiles are maxTiles = 1000 (>>n or just >=n)
maxTiles = 1000;
x = linspace(0,30);
tiledlayout('flow')
n = randi([1 10]);
for i=1:n
nexttile([1 maxTiles])
y = rand(1,numel(x));
plot(x,y)
end
Scott on 20 Aug 2020
Thank you! That does work flawlessly indeed. I did read that documentation before, and I would not have thought to use it in this way.

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