How to convert logical into decimal number?
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I have matrix C size 1x1013 cell. Each cell has different size.
<1x16 logical> <1x53 logical> <1x41 logical> <1x37 logical> <1x50 logical> <1x48 logical> and so on.
I want to convert each cell on matrix C into decimal number. I have tried use bin2dec but it doesn't worked.
For anyhelp, thank you.
7 Comments
Accepted Answer
Jan
on 13 Jan 2013
Assuming that the highest significant bit comes on the left:
C = {logical(randi(2,1,10) - 1), logical(randi(2,1,40) - 1)};
P2 = transpose(2 .^ (52:-1:0));
D = zeros(size(C));
for iD = 1:numel(D)
aC = C{iD};
D(iD) = aC * P2(54 - length(aC):53);
end
This is much more efficient than converting the logical vector to a string, the string to a double vector (inside bin2dec) and wrap this by cellfun and a slow anoymous function. I am really a fan of cellfun, but only, if it is efficient.
9 Comments
Walter Roberson
on 16 Jan 2013
Are you looking for strings as output, or numeric values? If you are looking for numeric values as output, you are not going to be able to produce that for more than 53 bits, fewer if you want to encode your numeric base in decimal (e.g., 333 decimal to mean 4^3 - 1 in base 4).
Longer numbers can be constructed as symbolic numbers if you have the symbolic toolbox, or there is John D'Errico's vpi (Variable Precision Integer) contribution.
Jan
on 16 Jan 2013
@Anisa: It would be helpful, if you answer the questions in the comments. Please explain, what you exactly want as output and do not let us guess the details. Thanks.
More Answers (1)
José-Luis
on 13 Jan 2013
a = randi(2,1,10)-1;
a = logical(a);
a = [{a};{a}]; %some cell array with logical values inside
%Turning into a string and then into a decimal number
your_vals = cellfun(@(x) bin2dec(sprintf('%i',x)),a);
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