Code Block of Operates in Image Processing
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    Rooter Boy
 on 17 Nov 2020
  
    
    
    
    
    Commented: Image Analyst
      
      
 on 19 Nov 2020
            
I tried this:
%Take negative
%positiveImage = imread('cameraman.tif');
%negativeImage = 255 - positiveImage;
%imshow(negativeImage)
%or
1) a=imread('cameraman.tif');
d(:, :, 3) =255 - a(: ,:, 3);
d(: ,:, 2) = 255 - a(:, :, 2);
d(:, :, 1) =255 -a(:, :, 1);
imshow([a,d])
%log transformation with c=10
clc; clear all; close all;
f=imread('cameraman.tif')
g=rgb2gray(f);
c=input('Enter the constant value, c= 10');
[M,N]= size(g);
for x=1:M
for y=1:N
m= double(g(x,y));
z(x,y)= c. *log10(1+m);
end
end
imshow(f), figure, imshow(z);
%power-law with c=10, gamma=0.5
clc; clear all; close all;
RGB=imread(' cameraman.tif');
I=rgb2gray(RGB);
I=im2double(I);
[m,n]= size(I);
c=10;
g=[0.5];
for r= 1:length(g)
for p=1:m
for q=1:n
I3=(p,q) =c *I(p,q). ^ g(r);
end
end
figure, imshow(I3); title('Power law transformation'); xlabel('Gamma='), ylabel(g(r));
end
%contrast stretching
I=imread('cameraman.tif');
[m,n]=size(I);
figure, imshow(I);
minp=min(min(I));
maxp=max(max(I));
maxp=double(maxp);
minp=double(minp);
c=10;
d=255;
for i=1:m
    for j=1:n
        sonuc=(((d-c)/(maxp-minp))*(double(I(i,j))-minp))+c;
        B(i,j)=round(sonuc);
end
end
B=uint8(B);
figure, imshow(B);
0 Comments
Accepted Answer
  Image Analyst
      
      
 on 17 Nov 2020
        See the FAQ: How to process a sequence of files
In the middle of the loop, call a function that processes one image only and returns an output image.  Then call sprintf() to create an output name, then call imwrite() to save the output image to that output file name.
9 Comments
  Image Analyst
      
      
 on 19 Nov 2020
				Sorry, I don't know much about that topic and don't understand what or why you think something's wrong with the code.
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