How do you circshift progressive rows an increasing amount?

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If I have a matrix:
[nan nan nan nan nan]
[ 1a nan nan nan nan]
[ 1b 2b nan nan nan]
[ 1c 2c 3c nan nan]
[ 1d 2d 3d 4d nan]
I want to change it to this:
[ 1a 2b 3c 4d nan]
[ 1b 2c 3d nan nan]
[ 1c 2d nan nan nan]
[ 1d nan nan nan nan]
[nan nan nan nan nan]
I tried:
for K = 1:length(A)
A = circshift(A(:,K),K);
Thank you.
  4 Comments
Rik
Rik on 24 Nov 2020
I have edited my answer to include the edit I meant. Dynamically growing an array is a bad idea, as mlint is warning you. You should make it a habit of resolving every mlint warning. Either suppress them (right-click and select suppress warning on this line), or change the code.

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Accepted Answer

Rik
Rik on 23 Nov 2020
Edited: Rik on 24 Nov 2020
You need to index a column in A in your output as well.
for K = 1:size(A,2)
A(:,K) = circshift(A(:,K),K);
end
If you want to move every NaN to the bottom, you can also use the sort function.

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