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simple Matrix manipulation without for-loop needed

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Marko
Marko on 30 Dec 2020
Edited: Bruno Luong on 10 Jan 2021
Hello Community,
i need your help.
I have a matrix which size is (N+1,N+1). I have also some vectors with different length. The elements of these vectors contain integer numbers.
The code above is modifying the matrix L in such a way, that it reads at first the first elemtn of vector vec and it set the row with the index = vec(i) to zero. and set a 1 on L(index,index).
This is accomblished by a slow for loop.
Do you have any ideas how it could be done in a more faster and elegent way?
function L = modifyLDirichlet(L,vec)
for i=1:numel(vec)
L(vec(i),:) = 0;
L(vec(i),vec(i)) = 1;
end
end
Thank you for your advice!
Best,
MJ

Accepted Answer

Bruno Luong
Bruno Luong on 30 Dec 2020
L(vec,:) = 0;
L(sub2ind(size(L),vec,vec)) = 1;
  5 Comments
Bruno Luong
Bruno Luong on 10 Jan 2021
For sparse matrix you should avoid to set non-zero elements to 0 ad vice versa at the first place.
Never repeat sufficiently: Try to build sparse matrix is recommended using only once the command
S = sparse(I, J, S, ...)
if you look for efficiency.
But I find your comment a little off-topic, you never mention you have sparse matrix in your orginal question or when you make a comment "i have found a much faster solution" coming from no-where with no information to backup.
If you want to compare or improve speed with your specific need and matrix structure, please open another thread.
I'll stop comment on side topic.

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