Undefined function or variable
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I am getting this error even though I have defined the "mat" function in my code. "Undefined function or variable 'mat'." I did some research but I can't find the reason. Because the code is too long, I do not share it all, but I share the relevant part below. other parts of the code are working.
Thanks in advance for your answers.
counter=0;
converg=1;
while converg>0.01;
for j = 2:n-1
min = 1000;
for l = 2:m-1
if number(j,l)~=0 && number(j,l) < min
min = number(j,l);
end
end
for i = 2:m-1
if index(j,i)~=0
n2 = number(j,i);
n1 = n2 - min +1;
if n1 == 1
mat(n1,n1) = C(j,i);
mat(n1,n1+1) = E(j,i);
d(n1,1) = (-1) * (P(j-1,i) * N(j,i)+P(j+1,i)*S(j,i))+Q(j,i);
end
if n1 == max(number(j,:)) - min +1
mat(n1,n1) = C(j,i);
mat(n1,n1-1) = W(j,i);
d(n1,1) = (-1) * (P(j-1,i) * N(j,i)+P(j+1,i)*S(j,i))+Q(j,i);
end
if n1~=1 && n1 ~= max(number(j,:))-min+1
mat(n1,n1) = C(j,i);
mat(n1,n1-1) = W(j,i);
mat(n1,n1+1) = E(j,i);
d(n1,1) = (-1) * (P(j-1,i) * N(j,i)+P(j+1,i)*S(j,i))+Q(j,i);
end
end
end
Pwf = thm(mat,d);
for i = 2:m-1
if index(j,i)~=0
n2 = number(j,i);
n1 = n2 - min +1;
P(j,i) = Pwf(n1,1);
end
end
clear Ps
clear mat
clear d
end
Pdiff = abs(Pold - P);
converg = max(max(Pdiff));
Pold = P;
counter = counter + 1
end
5 Comments
Star Strider
on 10 Jan 2021
The error (that should have been part of the orignal post) is:
Unrecognized function or variable 'n'.
referring to:
for j = 2:n-1
The obvious solution is to define ‘n’ (as an integer greater than 2) prior to the while loop.
If the error refers to the ‘mat’ variable (I dio not see a ‘mat’ function defined anywhere), note that it is possible that it might not be assigned if the if blocks prevent that assignment because the relevant conditions are not met.
muharrem çevik
on 10 Jan 2021
Star Strider
on 10 Jan 2021
My pleasure.
Supply the missing ingredients and you may get a useful response.
Walter Roberson
on 10 Jan 2021
min = number(j,l);
We recommend against using min or max as the names of variables, as it is very common to find that later in the same function one wants to use the min() or max() function. It also confuses readers, who would have to look carefully at the flow of code
muharrem çevik
on 11 Jan 2021
Answers (0)
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