Nested loop in 3 d matrix

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Mohammad Juned
Mohammad Juned on 12 Mar 2021
Commented: Mohammad Juned on 12 Mar 2021
I have a matrix of order 3*7
12 10 8 22 18 20 30
10 5 12 18 15 22 28
13 30 32 12 11 16 25
I want to add each element of every to each element of other rows
i.e. a1 a2 a3 a4 a5 a6 a7
c1 c2 c3 c4 c5 c6 c7 b1 b1 . . . . .
c1 c2 c3 c4 c5 c6 c7 b2 b2 . . . . .
c1 c2 c3 c4 c5 c6 c7 b3 b3 . . . . .
c1 c2 c3 c4 c5 c6 c7 b4 b4 . . . . .
c1 c2 c3 c4 c5 c6 c7 b5 b5 . . . . .
c1 c2 c3 c4 c5 c6 c7 b6 b6 . . . . .
c1 c2 c3 c4 c5 c6 c7 b7 b7 . . . . .
How can I do this using for loop ?
  2 Comments
David Hill
David Hill on 12 Mar 2021
Hard to understand. Show the output you want using a smaller input matrix.
Mohammad Juned
Mohammad Juned on 12 Mar 2021
Edited: Mohammad Juned on 12 Mar 2021
let a a matrix of 3*3
1 2 3
4 5 6
7 8 9
now we add each element such as
1 + { (4+7) (4+8) (4+9)
(5+7) (5+8) (5+9)
(6+7) (6+8) (6+9) }
2+{ (4+7) (4+8) (4+9)
(5+7) (5+8) (5+9)
(6+7) (6+8) (6+9) }
3+{ (4+7) (4+8) (4+9)
(5+7) (5+8) (5+9)
(6+7) (6+8) (6+9) }
since this is a matrix of 3*3 order size therefore we have 3*3*3 i.e.27 elements in it.
for 3*7 we would have 7*7*7 i.e. 343 elements.

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Accepted Answer

David Hill
David Hill on 12 Mar 2021
m=[12 10 8 22 18 20 30
10 5 12 18 15 22 28
13 30 32 12 11 16 25];
b=m(3,:)+m(2,:)';
for k=1:size(m,2)
M(:,:,k)=m(1,k)+b;
end
  9 Comments
David Hill
David Hill on 12 Mar 2021
It already is saved in a single matrix M.
Mohammad Juned
Mohammad Juned on 12 Mar 2021
I am using R2014a
I have to to do more operation on the matrix M. So can it be performed .

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