Calculate with initial value

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Jamil Arif
Jamil Arif on 15 May 2021
Edited: per isakson on 2 Jun 2021
i=1;
Z(i)=1;
while true
Z(i) =1 + B - q.*B.*(((Z(i))-B)./(((Z(i))-B*sigma)*((Z(i))+epsi*B)))-Z(i);
i=i+1;
end
  1 Comment
Sulaymon Eshkabilov
Sulaymon Eshkabilov on 15 May 2021
Note that in your set up "while" loop, Z(i) can't be on both sides of the equal sign. Z(i) on the left side has to be Z(i+1).

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Accepted Answer

per isakson
per isakson on 16 May 2021
There is nothing that terminates the execution of the loop when convergence is reached. Thus, the while-loop will run until the vector, Z, exceeds "Maximum possible array" or something else throws an error.
i=1;
Z(i)=1;
while true
Z(i+1) = 1 + B - q.*B.*(((Z(i))-B)./(((Z(i))-B*sigma)*((Z(i))+epsi*B)));
i = i+1;
end
Replace the loop by
tol = 1e-6;
i = 2;
Z(i) = 1;
Z(i-1) = Z(i)+2*tol;
while abs(Z(i)-Z(i-1)) >= tol
Z(i+1) = 1 + B - q.*B.*(((Z(i))-B)./(((Z(i))-B*sigma)*((Z(i))+epsi*B)));
i = i+1;
end
  2 Comments
Jamil Arif
Jamil Arif on 2 Jun 2021
Z(i-1) = Z(i)+2*tol;
what is the function for this part of the eqn
per isakson
per isakson on 2 Jun 2021
Edited: per isakson on 2 Jun 2021
The purpose of
Z(i-1) = Z(i)+2*tol;
is to make sure that
abs(Z(i)-Z(i-1)) >= tol
returns true and thus that the statements in the while-loop are executed for i equal to 2. Try to execute the code without it.

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