# Find in a cell array?

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M G on 7 Aug 2013
Commented: Marwan Malaeb on 20 May 2022
Hello all,
Suppose a cell array 10x1 consisted of random numbers from 1 to 5. How can I find the locations for number 5?
All the best,
MhD
Marwan Malaeb on 20 May 2022
call this array for example X
type k=find(X==5)
it will return for you the number of the cell that has the value of 5.

Jan on 7 Aug 2013
Edited: Jan on 7 Aug 2013
C = {1,5,3,4,2,3,4,5,2,1};
index = find([C{:}] == 5);
Here [C{:}] is a faster inlined version of cell2mat.
Alternative:
index = cellfun(@(x) x==5, C, 'UniformOutput', 1);
Or the long and most likely faster form:
index = false(1, numel(C))
for k = 1:numel(C)
index(k) = (C{k} == 5);
end
[EDITED] If you are talking of a cell string, this is much faster:
D = {'1' '5' '3' '4' '2' '3' '4' '5' '2' '1'};
index = find(strcmp(D, '5'));
Kylie Hansen on 16 Aug 2017
Just a casual MATLAB coder dropping by this older thread on a hunt for answers. Your response for the cell string method worked easily for me. Thank you so much for including it!

Bill Tubbs on 15 Feb 2022
Just in case someone comes here looking to do this with a cell array of chars as I was, it's quite easy this way:
my_cell_array = {'a', 'b', 'c'};
i = find(strcmp(my_cell_array, 'b'));
assert(i == 2)
hongyi xu on 17 Apr 2022
Genius! Your supplement exactly fits my question.

Caroline on 7 Aug 2013
Edited: Azzi Abdelmalek on 7 Aug 2013
cellarray_new = zeros; %initializing the array
ind = 1; %indices for new array
for j = 1:10
if (cellarray(j) == 5)
cellarray_new(ind) = j;
ind = ind + 1;
end
end
the array cellarray_new will contain all the indices of the original cell array that contain the number 5
Filza Ashraf on 22 May 2014
how can i find a pixel intensity if cell contains an image or image is stored in cell???