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George Adomako Kumi


Last seen: 1 year ago Active since 2020

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How do i further simplify this solution in matlab. I have used the simplify(.....) but it still gives me the same solution with the sin functions.
syms z syms L syms z1 syms za z1= 0.5*L; pi = 3.1412; L = 33.65; valueBxx1=int(sin(pi*z1/L)^2 ,z, 0, L);

1 year ago | 2 answers | 0

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I want help in writing a matlab code so that I wouldn't have to manually input the various steps as I have shown below. Thanks
E = 2900; % elastic modulus A = 15; % area Ix = 19; % modulus of inertia about x-axis Iy = 11; % modulus of inertia about...

2 years ago | 2 answers | 0

2

answers

Question


I need assistance in writing a code to solve iteratively this non-linear problem that I have broken down in the example below;
Q1 = [ 25, 10, 15, 20; 10, 12, 18, 23; 12, 15, 17,19; 15 20, 16, 28 ]; F1 = [ 6;7;12;7]; F2 = [ 48;64;72;75]; iter = 0; N ...

2 years ago | 0 answers | 0

0

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I need assistance in writing a matlab code for this iterative example
TRYING TO SOLVE FOR u and finding maximum iterations needed to solve Q1 = [ 25, 10, 15, 20; 10, 12, 18, 23; 12, 15, 17,19 ]; ...

2 years ago | 0 answers | 0

0

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How do I create a simple loop to sum up the elements in my matrix assuming some elements vary.
Tp1 = [ E*A1 E*Sx1 E*Sy1 E*Sw1 ; E*Sx1 E*Ix1 E*Ixy E*Iwy; E*Sy1 E*Ixy E*Iy1 E*Iwx ]; To1 = [ 0 0 0 0; 0 0 0 0; 0 0 0 0] ; Kt1=...

2 years ago | 1 answer | 0

1

answer

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How do I create a matrix block of 128x128 for the matrix below whilst wiping away the E value ( E=0) only in blocks 28 and 48.
E = 29000; A = 25; Ix = 39; Iy = 21; T = [ E*A 1 1 1; 1 E*Ix 1 1; 1 1 E*Iy 1];

2 years ago | 1 answer | 0

1

answer

Question


How do i write a line to display all the values that didn't meet the requirement
Limit = SigmaAp; if any (SigmaAx > SigmaAp) disp ('Some values above the limit.') else disp('All values are below th...

2 years ago | 2 answers | 0

2

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Question


Index in position 2 exceeds array bounds (must not exceed 1) - need help with getting this to work. thanks
for i = 1:NA for j= 1:NB Bxx(i,j) = ( a11(i,j)*a22(i,j)) - ( a12(i,j)*a21(i,j)) / a11(i,j); % Bxy(i,j) = ...

3 years ago | 0 answers | 0

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